one estimate for the number of protons in betelgeuse is 2. the mass of one proton is about 1.67×10^(-27) kg…

one estimate for the number of protons in betelgeuse is 2. the mass of one proton is about 1.67×10^(-27) kg. what is the mass of all the protons in betelgeuse? approximate by finding the product of (2×10^58)×(2×10^(-27)). (2×10^58)×(2×10^(-27)) =?×10^? kilograms

one estimate for the number of protons in betelgeuse is 2. the mass of one proton is about 1.67×10^(-27) kg. what is the mass of all the protons in betelgeuse? approximate by finding the product of (2×10^58)×(2×10^(-27)). (2×10^58)×(2×10^(-27)) =?×10^? kilograms

Answer

Explanation:

Step1: Multiply the non - exponential parts

Multiply 2 and 2. $2\times2 = 4$

Step2: Multiply the exponential parts

Use the rule $a^m\times a^n=a^{m + n}$. Here, $a = 10$, $m = 58$ and $n=-27$. So, $10^{58}\times10^{-27}=10^{58+( - 27)}=10^{31}$

Answer:

$4\times10^{31}$