in a parallel circuit with three resistors connected to a power source, what would happen to the equivalent…

in a parallel circuit with three resistors connected to a power source, what would happen to the equivalent resistance and current if you removed any one of the resistors?\nthe equivalent resistance would increase and the current would increase.\nthe equivalent resistance would increase and the current would decrease.\nthe equivalent resistance would decrease and the current would decrease.\nthe equivalent resistance would decrease and the current would increase.

in a parallel circuit with three resistors connected to a power source, what would happen to the equivalent resistance and current if you removed any one of the resistors?\nthe equivalent resistance would increase and the current would increase.\nthe equivalent resistance would increase and the current would decrease.\nthe equivalent resistance would decrease and the current would decrease.\nthe equivalent resistance would decrease and the current would increase.

Answer

Explanation:

Step1: Recall parallel - resistance formula

The formula for equivalent resistance $R_{eq}$ of resistors in parallel is $\frac{1}{R_{eq}}=\sum_{i = 1}^{n}\frac{1}{R_i}$. When $n = 3$, $\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$. If one resistor (say $R_3$) is removed, then $\frac{1}{R_{eq_{new}}}=\frac{1}{R_1}+\frac{1}{R_2}$. Since $\frac{1}{R_{eq_{new}}}<\frac{1}{R_{eq}}$, then $R_{eq_{new}}>R_{eq}$, so the equivalent resistance increases.

Step2: Apply Ohm's law

Ohm's law is $I=\frac{V}{R_{eq}}$. The voltage $V$ of the power - source is constant. Since $R_{eq}$ increases and $V$ is constant, according to the formula $I=\frac{V}{R_{eq}}$, the current $I$ will decrease.

Answer:

The equivalent resistance would increase and the current would decrease.