part 9 of 9 - analyze\nshakina and juliette set the cars initial velocity to zero and set the acceleration…

part 9 of 9 - analyze\nshakina and juliette set the cars initial velocity to zero and set the acceleration to +1.6 m/s², then clicked \start.\ answer the following questions.\nwhat is the cars displacement (in m) between 0 and 10.0 s?\n50 x\nyour response differs from the correct answer by more than 10%. double check your calculations. m\nwhat was the total distance traveled by the car (in m) during this time interval?\n4 x\nyour response differs significantly from the correct answer. rework your solution from the beginning and check each step carefully. m\nsubmit\nskip (you cannot come back)\nresources\nread it

part 9 of 9 - analyze\nshakina and juliette set the cars initial velocity to zero and set the acceleration to +1.6 m/s², then clicked \start.\ answer the following questions.\nwhat is the cars displacement (in m) between 0 and 10.0 s?\n50 x\nyour response differs from the correct answer by more than 10%. double check your calculations. m\nwhat was the total distance traveled by the car (in m) during this time interval?\n4 x\nyour response differs significantly from the correct answer. rework your solution from the beginning and check each step carefully. m\nsubmit\nskip (you cannot come back)\nresources\nread it

Answer

Explanation:

Step1: Identify the kinematic - equation

Since the initial velocity $u = 0\ m/s$, acceleration $a=1.6\ m/s^{2}$, and time $t = 10.0\ s$, we use the equation $s=ut+\frac{1}{2}at^{2}$.

Step2: Substitute the values

Plug $u = 0\ m/s$, $a = 1.6\ m/s^{2}$, and $t = 10.0\ s$ into the equation. We get $s=0\times t+\frac{1}{2}\times1.6\times(10.0)^{2}$.

Step3: Calculate the displacement

First, calculate $(10.0)^{2}=100$. Then, $\frac{1}{2}\times1.6\times100 = 80\ m$. Since the motion is in a straight - line and there is no change in direction (constant positive acceleration and starting from rest), the distance traveled is equal to the displacement.

Answer:

Displacement: $80\ m$ Distance traveled: $80\ m$