part a select the realistic problem for which these are the correct equations. be sure that the answer your…

part a select the realistic problem for which these are the correct equations. be sure that the answer your problem requests is consistent with the equation given. a 1000 kg race car enters a 25 m radius curve and accelerates around the curve for 10.0 s. the forward force provided by the cars wheels is 1500 n. after 10.0 s the car has moved 125 m around the track. find the initial and final angular velocities. a 1000 kg race car enters a 25 m radius curve and accelerates around the curve for 10.0 s. the forward force provided by the cars wheels is 1500 n. after 10.0 s the car has moved 125 m around the track. find the initial and final angular velocities. a 1000 kg race car enters a 50 m radius curve and accelerates around the curve for 15.0 s. the forward force provided by the cars wheels is 1500 n. after 15.0 s the car has moved 125 m around the track. find the initial and final angular velocities. a 1000 kg race car enters a 50 m radius curve and accelerates around the curve for 10.0 s. the forward force provided by the cars wheels is 1500 n. after 10.0 s the car has moved 125 m around the track. find the initial and final angular velocities. part b finish the solution of the problem. express your answer in radians per second. ωf = ωi+((1.5 m/s²)/(50 m))(10 s) 2.5 rad = 0 rad + ωi(10 s)+((1.5 m/s²)²/2(50 m))(10 s)² ωf =
Answer
Explanation:
Step1: Identify the angular - kinematic equation
The equation for angular velocity $\omega_f=\omega_i+\alpha t+\frac{1}{2}\alpha t^2$ is used, where $\omega_i$ is the initial angular velocity, $\alpha$ is the angular acceleration, and $t$ is the time. First, we need to find the linear acceleration $a$ and then the angular acceleration $\alpha=\frac{a}{r}$ (where $r$ is the radius of the curve). The linear acceleration $a$ can be related to the force $F$ by $F = ma$ (Newton's second law, $m = 1000$ kg and $F=1500$ N), so $a=\frac{F}{m}$.
Step2: Calculate the linear acceleration
Given $F = 1500$ N and $m = 1000$ kg, using $a=\frac{F}{m}$, we have $a=\frac{1500}{1000}=1.5$ m/s².
Step3: Calculate the angular acceleration
For a curve of radius $r = 50$ m, $\alpha=\frac{a}{r}=\frac{1.5}{50}=0.03$ rad/s². Given $\omega_i = 0$ rad/s and $t = 10$ s.
Step4: Calculate the final angular velocity
Using the equation $\omega_f=\omega_i+\alpha t$, substituting $\omega_i = 0$ rad/s, $\alpha=0.03$ rad/s² and $t = 10$ s, we get $\omega_f=0+(0.03\times10)=0.3$ rad/s.
Answer:
$0.3$ rad/s