a photon has 8.0×10⁻¹⁵ j of energy. plancks constant is 6.63×10⁻³⁴ j·s. what is the frequency of the photon…

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h\nu$, where $E$ is energy, $h$ is Planck's constant, and $\nu$ is frequency. We need to solve for $\nu$, so $\nu=\frac{E}{h}$.

Step2: Substitute given values

We know that $E = 8.0\times10^{-15}\text{ J}$ and $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$. Then $\nu=\frac{8.0\times 10^{-15}\text{ J}}{6.63\times 10^{-34}\text{ J}\cdot\text{s}}$.

Step3: Calculate the frequency

$\nu=\frac{8.0}{6.63}\times10^{-15 + 34}\text{ Hz}\approx1.21\times10^{19}\text{ Hz}$

Answer:

$1.21\times 10^{19}\text{ Hz}$ (corresponds to the first option)