a photon has a frequency of 7.3×10⁻¹⁷ hz. planck’s constant is 6.63×10⁻³⁴ j·s. the energy of the photon, to…

a photon has a frequency of 7.3×10⁻¹⁷ hz. planck’s constant is 6.63×10⁻³⁴ j·s. the energy of the photon, to the nearest tenths place, is ×10⁻⁵⁰ j.
Answer
Answer:
$4.8$
Explanation:
Step1: Recall energy - frequency formula
$E = h\nu$ where $E$ is the energy of the photon, $h$ is Planck's constant, and $\nu$ is the frequency of the photon.
Step2: Substitute given values
$h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$ and $\nu=7.3\times 10^{17}\text{ Hz}$ $E=(6.63\times 10^{-34})\times(7.3\times 10^{17})$
Step3: Use exponent - multiplication rule
$a^m\times a^n=a^{m + n}$ $E=(6.63\times7.3)\times10^{-34 + 17}$ $E = 48.399\times10^{-17}$ $E=4.8399\times 10^{-16}\text{ J}$ We want the answer in the form of $x\times 10^{-50}\text{ J}$. Since $4.8399\times 10^{-16}=4.8399\times10^{34}\times10^{-50}$, to the nearest tenths place, $x = 4.8$.