a photon has a frequency of 2.9×10⁻¹⁶ hz. plancks constant is 6.63×10⁻³⁴ j·s. the energy of the photon, to…

a photon has a frequency of 2.9×10⁻¹⁶ hz. plancks constant is 6.63×10⁻³⁴ j·s. the energy of the photon, to the nearest tenths place, is ×10⁻⁴⁹ j.
Answer
Explanation:
Step1: Recall energy - frequency formula
The energy of a photon is given by $E = h\nu$, where $E$ is the energy, $h$ is Planck's constant, and $\nu$ is the frequency.
Step2: Substitute given values
We have $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$ and $\nu=2.9\times 10^{-16}\text{ Hz}$. So $E=(6.63\times 10^{-34})\times(2.9\times 10^{-16})$. Using the rule of exponents $a^m\times a^n=a^{m + n}$, we get $E=(6.63\times2.9)\times10^{-34-16}$. $6.63\times2.9 = 19.227$, and $-34-16=-50$. So $E = 19.227\times10^{-50}=1.9227\times 10^{-49}\text{ J}$.
Step3: Round to nearest tenths place
Rounding $1.9227$ to the nearest tenths place gives $1.9$.
Answer:
$1.9$