v = d/t\nphysics 22\nvelocity quiz\nname:\nshow all work for full credit.\nq1. answer the following…

Explanation:

Step1: Calculate total distance

The total distance is the sum of the absolute - value of the displacement in each stage. From the velocity - time graph, we need to find the area under the curve. For (0 - 2s), (v = 1m/s), (d_1=1\times2 = 2m); for (2 - 4s), (v = 0m/s), (d_2 = 0); for (4 - 6s), (v=- 1m/s), (d_3=\vert-1\times2\vert = 2m); for (6 - 7s), (v = 0m/s), (d_4 = 0). The total distance (d=d_1 + d_2+d_3 + d_4=2 + 0+2 + 0=4m).

Step2: Calculate average velocity

The average velocity (v_{avg}=\frac{\Delta x}{\Delta t}). The displacement (\Delta x) is the net change in position. The area under the velocity - time graph gives displacement. The area above the (t) - axis is positive displacement and below is negative displacement. The area of the part above the (t) - axis from (0 - 2s) is (A_1=1\times2 = 2m), and the area of the part below the (t) - axis from (4 - 6s) is (A_2=-1\times2=-2m). So the net displacement (\Delta x=2+( - 2)=0m). The total time (\Delta t = 7s). So the average velocity (v_{avg}=\frac{0}{7}=0m/s).

Answer:

a) (4m) b) (0m/s)