6. a piece of lead metal had a mass of 217.90 grams. bob determined the volume by water displacement. the…
6. a piece of lead metal had a mass of 217.90 grams. bob determined the volume by water displacement. the volume of water was 30.6 ml. the volume of water and lead was 49.8 ml. calculate the density of the lead. d = \\(\\frac{m}{v}\\) 7. what is the volume, in centimeters cubed, of a block of steel (density of steel 7.85 g/cm³), which has a mass of 49.6 grams?
Answer
Explanation:
Step1: Calculate the volume of lead
The volume of lead $V$ is the volume of water and lead minus the volume of water. $V = 49.8 - 30.6=19.2$ mL. Since 1 mL = 1 $cm^{3}$, $V = 19.2$ $cm^{3}$.
Step2: Calculate the density of lead
The density formula is $D=\frac{m}{V}$, where $m = 217.90$ g and $V = 19.2$ $cm^{3}$. $D=\frac{217.90}{19.2}\approx11.35$ g/$cm^{3}$
Step3: Calculate the volume of steel
For the steel block, using the density formula $D=\frac{m}{V}$, we can re - arrange it to $V=\frac{m}{D}$. Given $m = 49.6$ g and $D = 7.85$ g/$cm^{3}$. $V=\frac{49.6}{7.85}\approx6.32$ $cm^{3}$
Answer:
The density of the lead is approximately 11.35 g/$cm^{3}$ and the volume of the steel block is approximately 6.32 $cm^{3}$