a player pushes a 0.250 kg hockey puck over frictionless ice with a constant force, causing it to accelerate…

a player pushes a 0.250 kg hockey puck over frictionless ice with a constant force, causing it to accelerate at 24 m/s² over a distance of 0.50 meters. what is the work done by the hockey player on the puck?
Answer
Explanation:
Step1: Find the force using Newton's second law
Newton's second law is ( F = ma ), where ( m = 0.250 , \text{kg} ) and ( a = 24 , \text{m/s}^2 ). ( F = 0.250 \times 24 = 6 , \text{N} )
Step2: Calculate work using the work formula
The work formula is ( W = Fd ), where ( F = 6 , \text{N} ) and ( d = 0.50 , \text{m} ). ( W = 6 \times 0.50 = 3 , \text{J} )
Answer:
The work done by the hockey player on the puck is ( 3 , \text{J} ).