pmug = +6.8 kg m/s pcup = -5.5 kg m/s\nwhat is the total momentum of the system?
pmug = +6.8 kg m/s pcup = -5.5 kg m/s\nwhat is the total momentum of the system?
Answer
Explanation:
Step1: Identify the momenta
The momentum of the mug is $P_{mug}= + 6.8\ kg\cdot m/s$ and the momentum of the cup is $P_{cup}=-5.5\ kg\cdot m/s$.
Step2: Calculate total momentum
The total momentum $P_{total}$ of the system is the sum of the momenta of the mug and the cup. So $P_{total}=P_{mug}+P_{cup}$. $P_{total}=6.8+( - 5.5)$ $P_{total}=6.8 - 5.5$ $P_{total}=1.3\ kg\cdot m/s$
Answer:
$1.3\ kg\cdot m/s$