the potential difference across two plates is 1.50 v. if the plates are 8.22*10^-4 m apart, what is the…

the potential difference across two plates is 1.50 v. if the plates are 8.22*10^-4 m apart, what is the electric field between them? (unit = n/c)

the potential difference across two plates is 1.50 v. if the plates are 8.22*10^-4 m apart, what is the electric field between them? (unit = n/c)

Answer

Explanation:

Step1: Recall electric - field formula

The formula for the electric field $E$ between two parallel plates is $E=\frac{V}{d}$, where $V$ is the potential difference and $d$ is the distance between the plates.

Step2: Substitute given values

Given $V = 1.50\ V$ and $d=8.22\times 10^{-4}\ m$. Substitute these values into the formula: $E=\frac{1.50}{8.22\times 10^{-4}}$.

Step3: Calculate the result

$E=\frac{1.50}{8.22\times 10^{-4}}\approx1825\ N/C$.

Answer:

$1825\ N/C$