the potential difference across two plates is 1.50 v. if the plates are 8.22*10^-4 m apart, what is the…

the potential difference across two plates is 1.50 v. if the plates are 8.22*10^-4 m apart, what is the electric field between them? (unit = n/c)
Answer
Explanation:
Step1: Recall electric - field formula
The formula for the electric field $E$ between two parallel plates is $E=\frac{V}{d}$, where $V$ is the potential difference and $d$ is the distance between the plates.
Step2: Substitute given values
Given $V = 1.50\ V$ and $d=8.22\times 10^{-4}\ m$. Substitute these values into the formula: $E=\frac{1.50}{8.22\times 10^{-4}}$.
Step3: Calculate the result
$E=\frac{1.50}{8.22\times 10^{-4}}\approx1825\ N/C$.
Answer:
$1825\ N/C$