what is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant…

Explanation:

Step1: Identify the formula

The formula for elastic - potential energy of a spring is $U = \frac{1}{2}kx^{2}$, where $k$ is the spring constant and $x$ is the displacement from the equilibrium position.

Step2: Substitute the given values

We are given that $k = 95\ N/m$ and $x=0.65\ m$. Substitute these values into the formula: $U=\frac{1}{2}\times95\times(0.65)^{2}$.

Step3: Calculate the value

First, calculate $(0.65)^{2}=0.4225$. Then, $\frac{1}{2}\times95\times0.4225 = 47.5\times0.4225=20.06875\approx20\ J$.

Answer:

20 J