the potential energy, p, in a spring is represented using the formula $p = \\frac{1}{2}kx^{2}$. lupe uses an…

the potential energy, p, in a spring is represented using the formula $p = \\frac{1}{2}kx^{2}$. lupe uses an equivalent equation, which is solved for k, to determine the answers to her homework. which equation should she use? $k = 2px^{2}$ $k = \\frac{1}{2}px^{2}$ $k = \\frac{2p}{x^{2}}$ $k = \\frac{p}{2x^{2}}$

the potential energy, p, in a spring is represented using the formula $p = \\frac{1}{2}kx^{2}$. lupe uses an equivalent equation, which is solved for k, to determine the answers to her homework. which equation should she use? $k = 2px^{2}$ $k = \\frac{1}{2}px^{2}$ $k = \\frac{2p}{x^{2}}$ $k = \\frac{p}{2x^{2}}$

Answer

Explanation:

Step1: Isolate k in the formula

Given $P=\frac{1}{2}kx^{2}$. Multiply both sides by 2 to get rid of the fraction: $2P = kx^{2}$.

Step2: Solve for k

Divide both sides of the equation $2P = kx^{2}$ by $x^{2}$ to isolate k. So, $k=\frac{2P}{x^{2}}$.

Answer:

$k=\frac{2P}{x^{2}}$ (corresponds to the third - option in the multiple - choice list)