predict the missing component in the nuclear equation. \n$_{38}^{90}\\text{sr} \\rightarrow…

predict the missing component in the nuclear equation. \n$_{38}^{90}\\text{sr} \\rightarrow _{39}^{90}\\text{y} + x$\noptions:\n$_{2}^{4}\\text{he}$\n$_{-1}^{0}\\text{e}$\n$_{0}^{0}\\gamma$

predict the missing component in the nuclear equation. \n$_{38}^{90}\\text{sr} \\rightarrow _{39}^{90}\\text{y} + x$\noptions:\n$_{2}^{4}\\text{he}$\n$_{-1}^{0}\\text{e}$\n$_{0}^{0}\\gamma$

Answer

Explanation:

Step1: Balance mass numbers

Let mass number of X be $A$. $90 = 90 + A$ $A = 90 - 90 = 0$

Step2: Balance atomic numbers

Let atomic number of X be $Z$. $38 = 39 + Z$ $Z = 38 - 39 = -1$

Answer:

$\boldsymbol{_{-1}^{0}e}$