as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if…

as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant? (1 point)\nthe volume decreases to half of its original value\nthe volume decreases to one - fourth of its original value\nthe volume increases to twice its original value\nthe volume increases to four times its original value

as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant? (1 point)\nthe volume decreases to half of its original value\nthe volume decreases to one - fourth of its original value\nthe volume increases to twice its original value\nthe volume increases to four times its original value

Answer

Explanation:

Step1: Recall Boyle's law

$P_1V_1 = P_2V_2$ (constant - temperature)

Step2: Let $P_2=\frac{1}{2}P_1$

$P_1V_1=\frac{1}{2}P_1V_2$

Step3: Solve for $V_2$

Divide both sides by $\frac{1}{2}P_1$, we get $V_2 = 2V_1$

Answer:

The volume increases to twice its original value