as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if…
as the pressure of a gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant? (1 point)\nthe volume decreases to one - fourth of its original value.\nthe volume increases to four times its original value.\nthe volume increases to twice its original value.\nthe volume decreases to half of its original value.
Answer
Explanation:
Step1: Recall Boyle's Law
Boyle's law states that $P_1V_1 = P_2V_2$ for a given mass of gas at constant temperature, where $P_1$ and $V_1$ are the initial pressure and volume, and $P_2$ and $V_2$ are the final pressure and volume.
Step2: Set up the relationship
Let the initial pressure be $P_1$ and volume be $V_1$, and the final pressure $P_2=\frac{1}{2}P_1$. Substitute into Boyle's law: $P_1V_1=\frac{1}{2}P_1V_2$.
Step3: Solve for $V_2$
Divide both sides of the equation $P_1V_1=\frac{1}{2}P_1V_2$ by $\frac{1}{2}P_1$. We get $V_2 = 2V_1$.
Answer:
The volume increases to twice its original value.