the pressure that a gas exerts on a sealed container changes from 53.0 atm to 35.2 atm. what is the initial…

the pressure that a gas exerts on a sealed container changes from 53.0 atm to 35.2 atm. what is the initial temperature of the gas if the final temperature is 12.0 °c? t = ? °c

the pressure that a gas exerts on a sealed container changes from 53.0 atm to 35.2 atm. what is the initial temperature of the gas if the final temperature is 12.0 °c? t = ? °c

Answer

Explanation:

Step1: Convert final temperature to Kelvin

$T_2=12.0 + 273.15=285.15\ K$

Step2: Apply Gay - Lussac's Law ($\frac{P_1}{T_1}=\frac{P_2}{T_2}$)

$T_1=\frac{P_1T_2}{P_2}$

Step3: Substitute values

$T_1=\frac{53.0\ atm\times285.15\ K}{35.2\ atm}\approx429.9\ K$

Step4: Convert back to Celsius

$T_1 = 429.9 - 273.15=156.75^{\circ}C$

Answer:

$156.75^{\circ}C$