the pressure that a gas exerts on a sealed container changes from 3.74 atm to a new pressure when the…

Explanation:

Step1: Identify the gas - law formula

For a fixed amount of gas in a sealed container (constant volume), we use Gay - Lussac's law: $\frac{P_1}{T_1}=\frac{P_2}{T_2}$.

Step2: Rearrange the formula to solve for $P_2$

$P_2=\frac{P_1T_2}{T_1}$.

Step3: Substitute the given values

Given $P_1 = 3.74$ atm, $T_1=394$ K, and $T_2 = 789$ K. Then $P_2=\frac{3.74\times789}{394}$.

Step4: Calculate the value of $P_2$

$P_2=\frac{3.74\times789}{394}=\frac{2940.86}{394}\approx7.46$ atm.

Answer:

$7.46$ atm