problem 7: (6% of assignment value) three capacitors are connected as shown, where c = 0.015 f. part (a)…

problem 7: (6% of assignment value) three capacitors are connected as shown, where c = 0.015 f. part (a) input an expression for the equivalent capacitance between points a and b, in terms of c. hints: 4% deduction per hint. hints remaining: 2 feedback: 5% deduction per feedback. grade summary deductions potential submissions attempt(s) remaining: 3 4% deduction per attempt detailed view

problem 7: (6% of assignment value) three capacitors are connected as shown, where c = 0.015 f. part (a) input an expression for the equivalent capacitance between points a and b, in terms of c. hints: 4% deduction per hint. hints remaining: 2 feedback: 5% deduction per feedback. grade summary deductions potential submissions attempt(s) remaining: 3 4% deduction per attempt detailed view

Answer

Explanation:

Step1: Identify capacitor - combination rules

For capacitors in parallel, (C_{eq - parallel}=C_1 + C_2+\cdots), and for capacitors in series, (\frac{1}{C_{eq - series}}=\frac{1}{C_1}+\frac{1}{C_2}+\cdots). First, note that (3C) and (2C) are in parallel.

Step2: Calculate the equivalent of (3C) and (2C) in parallel

(C_{1}=3C + 2C=5C) (using the parallel - capacitor formula).

Step3: Calculate the equivalent of (C_{1}) and (5C) in series

Since (C_{1} = 5C) and the other capacitor is (5C), and they are in series, (\frac{1}{C_{eq}}=\frac{1}{5C}+\frac{1}{5C}=\frac{2}{5C}). Then, (C_{eq}=\frac{5C}{2}).

Answer:

(\frac{5C}{2})