a projectile is launched at a 30° angle relative to the ground. the projectile has an initial velocity of 15…

a projectile is launched at a 30° angle relative to the ground. the projectile has an initial velocity of 15 m/s and travels through the air for 2 seconds. the horizontal displacement of the projectile, rounded to the nearest hundredth, is m.

a projectile is launched at a 30° angle relative to the ground. the projectile has an initial velocity of 15 m/s and travels through the air for 2 seconds. the horizontal displacement of the projectile, rounded to the nearest hundredth, is m.

Answer

Explanation:

Step1: Find horizontal - component of initial velocity

The formula for the horizontal - component of velocity is $v_{x}=v_{0}\cos\theta$, where $v_{0}$ is the initial velocity and $\theta$ is the launch angle. Given $v_{0} = 15$ m/s and $\theta = 30^{\circ}$, we have $v_{x}=15\cos30^{\circ}=15\times\frac{\sqrt{3}}{2}\approx15\times0.866 = 12.99$ m/s.

Step2: Calculate horizontal displacement

The formula for horizontal displacement is $x = v_{x}t$, where $t$ is the time - of - flight. Given $t = 2$ s and $v_{x}\approx12.99$ m/s, then $x=12.99\times2 = 25.98$ m.

Answer:

$25.98$