quel graphique de fonction de transition correspond au réseau à quatre bornes dont le circuit est représenté…

Explanation:

Step1: Analyze RL - circuit transfer function

The given circuit is an RL - series circuit. The transfer function (H(s)=\frac{U_{out}(s)}{U_{in}(s)}=\frac{sL}{sL + R}). Taking the inverse - Laplace transform for a step input (U_{in}(s)=\frac{1}{s}), we get (u_{out}(t)=1 - e^{-\frac{R}{L}t}).

Step2: Match with graphs

The function (u_{out}(t)=1 - e^{-\frac{R}{L}t}) is a rising exponential function that starts from (0) and approaches (1) as (t\rightarrow\infty). Graph 'c' shows a function that starts from (0) and rises asymptotically to a non - zero value, which is consistent with the behavior of the output of the RL circuit for a step input.

Answer:

C. c