question 1 of 10\nfour students measured the acceleration of gravity. the accepted value for their location…

question 1 of 10\nfour students measured the acceleration of gravity. the accepted value for their location is 9.78 m/s². which students measurement has the largest percent error?\na. student 2: 9.79 m/s²\nb. student 3: 9.88 m/s²\nc. student 1: 9.78 m/s²\nd. student 4: 9.61 m/s²

question 1 of 10\nfour students measured the acceleration of gravity. the accepted value for their location is 9.78 m/s². which students measurement has the largest percent error?\na. student 2: 9.79 m/s²\nb. student 3: 9.88 m/s²\nc. student 1: 9.78 m/s²\nd. student 4: 9.61 m/s²

Answer

Explanation:

Step1: Recall percent - error formula

Percent error = $\left|\frac{\text{measured value}-\text{accepted value}}{\text{accepted value}}\right|\times100%$

Step2: Calculate percent - error for Student 2

Percent error of Student 2 = $\left|\frac{9.79 - 9.78}{9.78}\right|\times100%=\left|\frac{0.01}{9.78}\right|\times100%\approx0.10%$

Step3: Calculate percent - error for Student 3

Percent error of Student 3 = $\left|\frac{9.88 - 9.78}{9.78}\right|\times100%=\left|\frac{0.1}{9.78}\right|\times100%\approx1.02%$

Step4: Calculate percent - error for Student 1

Percent error of Student 1 = $\left|\frac{9.78 - 9.78}{9.78}\right|\times100% = 0%$

Step5: Calculate percent - error for Student 4

Percent error of Student 4 = $\left|\frac{9.61 - 9.78}{9.78}\right|\times100%=\left|\frac{- 0.17}{9.78}\right|\times100%\approx1.74%$

Answer:

D. Student 4: 9.61 m/s²