question 10 (1 point)\n(02.07 mc)\nif a box with a mass of 8.0 kg is sitting on a frictionless surface…

question 10 (1 point)\n(02.07 mc)\nif a box with a mass of 8.0 kg is sitting on a frictionless surface experiences an acceleration of 4.0 m/s2 to the right, what is the net force acting on the box?\n a 2.0 n\n b 12 n\n c 32 n\n d 45 n

question 10 (1 point)\n(02.07 mc)\nif a box with a mass of 8.0 kg is sitting on a frictionless surface experiences an acceleration of 4.0 m/s2 to the right, what is the net force acting on the box?\n a 2.0 n\n b 12 n\n c 32 n\n d 45 n

Answer

Explanation:

Step1: Recall Newton's second law

$F = ma$

Step2: Substitute given values

$m = 8.0\ kg$, $a=4.0\ m/s^{2}$, so $F=(8.0\ kg)\times(4.0\ m/s^{2})$

Step3: Calculate the net - force

$F = 32\ N$

Answer:

C. 32 N