question 4 of 10\na point at the end of a propeller has a centripetal acceleration of 532.6 m/s². if the…

question 4 of 10\na point at the end of a propeller has a centripetal acceleration of 532.6 m/s². if the velocity of the propeller at this point is 35 m/s, how long is the propeller blade?\na. 2.5 m\nb. 1.9 m\nc. 2.3 m\nd. 2.1 m

question 4 of 10\na point at the end of a propeller has a centripetal acceleration of 532.6 m/s². if the velocity of the propeller at this point is 35 m/s, how long is the propeller blade?\na. 2.5 m\nb. 1.9 m\nc. 2.3 m\nd. 2.1 m

Answer

Explanation:

Step1: Recall centripetal - acceleration formula

The centripetal - acceleration formula is $a_c=\frac{v^{2}}{r}$, where $a_c$ is the centripetal acceleration, $v$ is the velocity, and $r$ is the radius (length of the propeller blade in this case). We need to solve for $r$, so we can re - arrange the formula to $r = \frac{v^{2}}{a_c}$.

Step2: Substitute given values

Given that $a_c = 532.6\ m/s^{2}$ and $v = 35\ m/s$. Substitute these values into the formula: $r=\frac{35^{2}}{532.6}=\frac{1225}{532.6}\approx2.3\ m$.

Answer:

C. 2.3 m