question 6 of 10\na television of mass 12 kg sits on a table. the coefficient of static friction between the…

question 6 of 10\na television of mass 12 kg sits on a table. the coefficient of static friction between the table and the television is 0.83. what is the minimum applied force that will cause the television to slide?\na. 118 n\nb. 98 n\nc. 83 n\nd. 75 n

question 6 of 10\na television of mass 12 kg sits on a table. the coefficient of static friction between the table and the television is 0.83. what is the minimum applied force that will cause the television to slide?\na. 118 n\nb. 98 n\nc. 83 n\nd. 75 n

Answer

Explanation:

Step1: Calculate the normal force

The normal force $N$ on a horizontal surface for an object of mass $m$ is equal to its weight $mg$. Given $m = 12\ kg$ and $g= 9.8\ m/s^{2}$, so $N=mg = 12\times9.8=117.6\ N$.

Step2: Calculate the maximum static - friction force

The formula for the maximum static - friction force $F_f=\mu_sN$, where $\mu_s = 0.83$ and $N = 117.6\ N$. So $F_f=0.83\times117.6\approx97.6\ N\approx98\ N$. The minimum applied force to make the television slide is equal to the maximum static - friction force.

Answer:

B. 98 N