question 12 of 25\njohn pushes forward on a car with a force of 300 n while bob pushes backward on the car…

question 12 of 25\njohn pushes forward on a car with a force of 300 n while bob pushes backward on the car with a force of 385 n. what is the net force on the car?\na. 85 n forward\nb. 685 n backward\nc. 685 n forward\nd. 85 n backward

question 12 of 25\njohn pushes forward on a car with a force of 300 n while bob pushes backward on the car with a force of 385 n. what is the net force on the car?\na. 85 n forward\nb. 685 n backward\nc. 685 n forward\nd. 85 n backward

Answer

Explanation:

Step1: Define forward as positive

Let the forward - direction force be positive and the backward - direction force be negative. John's force $F_J = 300N$ and Bob's force $F_B=- 385N$.

Step2: Calculate the net force

The net force $F_{net}=F_J + F_B$. Substitute the values: $F_{net}=300+( - 385)=300 - 385=-85N$.

Answer:

D. 85 N backward