question 14 of 29\na climber is attached to a vertical rope that has a tension of 789 n. if the climber has…

question 14 of 29\na climber is attached to a vertical rope that has a tension of 789 n. if the climber has a mass of 85 kg, what is the net force on the climber?\na: 789 n down\nb: 842 n up\nc: 48 n down\nd: 48 n up

question 14 of 29\na climber is attached to a vertical rope that has a tension of 789 n. if the climber has a mass of 85 kg, what is the net force on the climber?\na: 789 n down\nb: 842 n up\nc: 48 n down\nd: 48 n up

Answer

Explanation:

Step1: Calculate the weight of the climber

The weight formula is $F = mg$, where $m = 85\ kg$ and $g=9.8\ m/s^{2}$. So $F = 85\times9.8=833\ N$ (down - ward).

Step2: Analyze the tension force

The tension in the rope is $T = 785\ N$ (up - ward).

Step3: Calculate the net force

The net force $F_{net}=F - T$. Substitute the values: $F_{net}=833 - 785 = 48\ N$. Since the weight is greater than the tension, the net force is downward.

Answer:

C. 48 N down