question 20 of 25\na climber is attached to a vertical rope that has a tension of 785 n. if the climber has…

question 20 of 25\na climber is attached to a vertical rope that has a tension of 785 n. if the climber has a mass of 85 kg, what is the net force on the climber?\na. 542 n up\nb. 48 n up\nc. 700 n down\nd. 48 n down

question 20 of 25\na climber is attached to a vertical rope that has a tension of 785 n. if the climber has a mass of 85 kg, what is the net force on the climber?\na. 542 n up\nb. 48 n up\nc. 700 n down\nd. 48 n down

Answer

Explanation:

Step1: Calculate the gravitational force

The gravitational force formula is $F = mg$, where $m = 85$ kg and $g=9.8$ m/s². So $F = 85\times9.8=833$ N (down - ward direction).

Step2: Determine the net force

The tension in the rope is $T = 785$ N (up - ward direction). The net force $F_{net}=T - F$. Substitute the values: $F_{net}=785 - 833=- 48$ N. The negative sign indicates the direction is downward.

Answer:

D. 48 N down