question 20\n1 pts\nwhat type of radiation is present in the following nuclear decay reaction…

question 20\n1 pts\nwhat type of radiation is present in the following nuclear decay reaction: (^{210}_{85}at\rightarrow ^{0}_{- 1}e+^{210}_{86}rn)\nalpha\nbeta\ngamma

question 20\n1 pts\nwhat type of radiation is present in the following nuclear decay reaction: (^{210}_{85}at\rightarrow ^{0}_{- 1}e+^{210}_{86}rn)\nalpha\nbeta\ngamma

Answer

Brief Explanations:

In beta - decay, a neutron in the nucleus is converted into a proton, an electron (beta - particle), and an antineutrino. The electron is emitted from the nucleus. In the given reaction $^{210}{85}At\rightarrow ^{0}{ - 1}e+^{210}{86}Rn$, the atomic number of the parent nucleus ($At$) increases by 1 and a particle with a mass number of 0 and charge of - 1 (an electron) is emitted, which is characteristic of beta - decay. Alpha - decay involves the emission of a $^{4}{2}He$ nucleus, and gamma - decay involves the emission of high - energy photons without a change in mass number or atomic number.

Answer:

B. Beta