question 8 of 20\nview policies\ncurrent attempt in progress\nwhat is the frequency (in khz) of photons with…

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = h\nu$, where $E$ is the energy, $h$ is Planck's constant ($h=6.626\times 10^{- 34}\ J\cdot s$), and $\nu$ is the frequency. We need to solve for $\nu$.

Step2: Rearrange the formula for frequency

$\nu=\frac{E}{h}$. Substitute $E = 374\ J$ and $h = 6.626\times 10^{-34}\ J\cdot s$ into the formula: $\nu=\frac{374\ J}{6.626\times 10^{-34}\ J\cdot s}\approx5.64\times 10^{35}\ Hz$.

Step3: Convert Hz to kHz

Since $1\ kHz = 10^{3}\ Hz$, then $\nu=\frac{5.64\times 10^{35}\ Hz}{10^{3}\ Hz/kHz}=5.64\times 10^{32}\ kHz$.

Answer:

$5.64\times 10^{32}$