question 21 of 25\na motorcycle is capable of accelerating at 5.1 m/s². starting from rest, how far can it…

question 21 of 25\na motorcycle is capable of accelerating at 5.1 m/s². starting from rest, how far can it travel in 1.5 seconds?\na. 3.2 m\nb. 5.7 m\nc. 3.8 m\nd. 4.5 m

question 21 of 25\na motorcycle is capable of accelerating at 5.1 m/s². starting from rest, how far can it travel in 1.5 seconds?\na. 3.2 m\nb. 5.7 m\nc. 3.8 m\nd. 4.5 m

Answer

Explanation:

Step1: Identify the kinematic - equation

The kinematic equation for displacement with initial velocity $u = 0$ is $s=ut+\frac{1}{2}at^{2}$. Since $u = 0$ (starting from rest), the equation simplifies to $s=\frac{1}{2}at^{2}$.

Step2: Substitute the values

Given $a = 5.1\ m/s^{2}$ and $t = 1.5\ s$. Substitute these values into the equation $s=\frac{1}{2}\times5.1\times(1.5)^{2}$. First, calculate $(1.5)^{2}=2.25$. Then, $\frac{1}{2}\times5.1\times2.25 = 2.55\times2.25=5.7375\ m\approx5.7\ m$.

Answer:

B. 5.7 m