question 7 of 25\na box of mass 115 kg sits on an inclined surface with an angle of 59°. what is the…
question 7 of 25\na box of mass 115 kg sits on an inclined surface with an angle of 59°. what is the component of the weight of the box along the surface?\n\na. 966 n\nb. 581 n\nc. 619 n\nd. 1127 n
Answer
Explanation:
Step1: Calculate the weight of the box
The weight of an object is given by $W = mg$, where $m = 115$ kg and $g= 9.8$ m/s². So $W=115\times9.8 = 1127$ N.
Step2: Find the component of weight along the inclined - surface
The component of the weight along the inclined surface is $W_{parallel}=W\sin\theta$, where $\theta = 59^{\circ}$ and $W = 1127$ N. So $W_{parallel}=1127\times\sin(59^{\circ})\approx1127\times0.857 = 966$ N.
Answer:
A. 966 N