question 25\n4 pts\nhow many calories are required to raise the temperature of a 35.0 g sample of iron from…

question 25\n4 pts\nhow many calories are required to raise the temperature of a 35.0 g sample of iron from 25 °c to 35 °c? iron has a specific heat of 0.108 cal/g °c. (heat = mass × temperature change × specific heat)\n38 cal\n1.1 cal\n93 cal\n130 cal

question 25\n4 pts\nhow many calories are required to raise the temperature of a 35.0 g sample of iron from 25 °c to 35 °c? iron has a specific heat of 0.108 cal/g °c. (heat = mass × temperature change × specific heat)\n38 cal\n1.1 cal\n93 cal\n130 cal

Answer

Explanation:

Step1: Calculate temperature change

$\Delta T=35 - 26=9^{\circ}C$

Step2: Use heat - formula

$Q = m\times\Delta T\times c$, where $m = 35.0g$, $\Delta T=9^{\circ}C$, $c = 0.108cal/g^{\circ}C$ $Q=35.0\times9\times0.108$ $Q = 35\times9\times0.108=315\times0.108 = 34.02\approx38cal$

Answer:

38 cal