question 7 of 25\nto a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s…

question 7 of 25\nto a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the womans frame of reference, what is the mans velocity?\na. 4 m/s west\nb. 1 m/s west\nc. 4 m/s east\nd. 1 m/s east

question 7 of 25\nto a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the womans frame of reference, what is the mans velocity?\na. 4 m/s west\nb. 1 m/s west\nc. 4 m/s east\nd. 1 m/s east

Answer

Explanation:

Step1: Define velocities

Let the velocity of the man with respect to the stationary observer be $v_{m - s}=2.5\ m/s$ (east - positive direction) and the velocity of the woman with respect to the stationary observer be $v_{w - s}=- 1.5\ m/s$ (west - negative direction).

Step2: Use relative - velocity formula

The formula for relative velocity is $v_{m - w}=v_{m - s}-v_{w - s}$. Substitute the values: $v_{m - w}=2.5-(-1.5)$.

Step3: Calculate the result

$v_{m - w}=2.5 + 1.5=4\ m/s$. Since the result is positive, it is in the east direction.

Answer:

C. 4 m/s east