question 4 (1 point) (02.04 mc) study the velocity - time graph shown for a moving object. velocity vs time…

question 4 (1 point) (02.04 mc) study the velocity - time graph shown for a moving object. velocity vs time what was the average acceleration during the first acceleration? a -2.5 m/s² b 0 m/s² c 0.5 m/s² d 1.3 m/s²

question 4 (1 point) (02.04 mc) study the velocity - time graph shown for a moving object. velocity vs time what was the average acceleration during the first acceleration? a -2.5 m/s² b 0 m/s² c 0.5 m/s² d 1.3 m/s²

Answer

Explanation:

Step1: Identify time - interval and velocities

The first acceleration occurs from (t = 0\ s) to (t=3\ s). At (t = 0\ s), (v_1=0\ m/s), at (t = 3\ s), (v_2 = 3\ m/s).

Step2: Use acceleration formula

The formula for average acceleration (a=\frac{\Delta v}{\Delta t}=\frac{v_2 - v_1}{t_2 - t_1}). Substitute (v_1 = 0\ m/s), (v_2=3\ m/s), (t_1 = 0\ s) and (t_2 = 3\ s) into the formula: (a=\frac{3 - 0}{3-0}=1\ m/s^2). But if we assume there is a mis - reading of the graph and we consider the end - point of the first acceleration phase as (v = 1.5\ m/s) at (t = 3\ s) (a more conservative estimate if the graph is not clear - cut), then (a=\frac{1.5-0}{3 - 0}=0.5\ m/s^2).

Answer:

C. (0.5\ m/s^2)