question 6 (1 point)\n(02.05 mc)\nneglecting air resistance, how far does an object fall from rest after 3.0…

question 6 (1 point)\n(02.05 mc)\nneglecting air resistance, how far does an object fall from rest after 3.0 seconds?\n○ a 29 m\n○ b 44 m\n○ c 88 m\n○ d 220 m

question 6 (1 point)\n(02.05 mc)\nneglecting air resistance, how far does an object fall from rest after 3.0 seconds?\n○ a 29 m\n○ b 44 m\n○ c 88 m\n○ d 220 m

Answer

Explanation:

Step1: Identify the formula

Use the free - fall displacement formula $d = v_0t+\frac{1}{2}gt^2$. Since the object starts from rest, $v_0 = 0$. The acceleration due to gravity $g\approx9.8\ m/s^2$ and $t = 3.0\ s$.

Step2: Substitute values

Substitute $v_0 = 0$, $g = 9.8\ m/s^2$ and $t = 3.0\ s$ into the formula. We get $d=\frac{1}{2}\times9.8\times(3.0)^2$. First, calculate $(3.0)^2=9$. Then $\frac{1}{2}\times9.8\times9 = 4.9\times9=44.1\ m\approx44\ m$.

Answer:

B. 44 m