question 7 (1 point)\nuse the following information to answer the next question.\na tank contains 200 g of…

question 7 (1 point)\nuse the following information to answer the next question.\na tank contains 200 g of water maintained at temperature of 27 ° c. the water is heated to raise its temperature to 100 ° c. the heat energy required is x kj.\nthe value of x is\n83.6 kj\n61.3 kj\n62.3 kj\n60.2 kj\n63.2 kj

question 7 (1 point)\nuse the following information to answer the next question.\na tank contains 200 g of water maintained at temperature of 27 ° c. the water is heated to raise its temperature to 100 ° c. the heat energy required is x kj.\nthe value of x is\n83.6 kj\n61.3 kj\n62.3 kj\n60.2 kj\n63.2 kj

Answer

Explanation:

Step1: Convert mass to kg

Given mass of water (m = 200\space g=0.2\space kg)

Step2: Determine temperature change

Initial temperature (T_1 = 27^{\circ}C), final temperature (T_2 = 100^{\circ}C). Temperature change (\Delta T=T_2 - T_1=100 - 27 = 73^{\circ}C)

Step3: Use heat - energy formula

The specific heat capacity of water (c = 4.18\space kJ/(kg\cdot^{\circ}C)). The formula for heat energy (Q=mc\Delta T). Substitute (m = 0.2\space kg), (c = 4.18\space kJ/(kg\cdot^{\circ}C)) and (\Delta T = 73^{\circ}C) into the formula: [ \begin{align*} Q&=(0.2)\times(4.18)\times(73)\ &=0.2\times4.18\times73\ &=0.836\times73\ & = 61.028\approx61.3\space kJ \end{align*} ]

Answer:

(61.3\space kJ)