question 4 (2 points)\n(02.01 mc)\ne = mc²\nc =?\n○ a e/m\n○ b m/e\n○ c √(e/m)\n○ d √(m/e)

question 4 (2 points)\n(02.01 mc)\ne = mc²\nc =?\n○ a e/m\n○ b m/e\n○ c √(e/m)\n○ d √(m/e)

question 4 (2 points)\n(02.01 mc)\ne = mc²\nc =?\n○ a e/m\n○ b m/e\n○ c √(e/m)\n○ d √(m/e)

Answer

Explanation:

Step1: Isolate $c^{2}$

Given $E = mc^{2}$, divide both sides by $m$ to get $c^{2}=\frac{E}{m}$.

Step2: Solve for $c$

Take the square - root of both sides. Since $c$ represents the speed of light (a non - negative quantity in the context of the physical formula), $c=\sqrt{\frac{E}{m}}$.

Answer:

C. $\sqrt{(E/m)}$