question 2\n1 pts\na 2 kg object moving at 3 m/s will increase its velocity to 5 m/s after 2 m under the…

question 2\n1 pts\na 2 kg object moving at 3 m/s will increase its velocity to 5 m/s after 2 m under the action of a constant force parallel to a frictionless surface. the constant force acting on the object is:\n2 n\n4 n\n6 n\n8 n\n10 n\nquestion 3\n1 pts\nif the total work done on an object is positive,\nthe objects velocity will increase\nthe objects velocity will decrease.\nthe kinetic energy of the object will decrease.\nthe objects velocity will not change.\nthe direction of the objects acceleration will be opposite to its displacement.

question 2\n1 pts\na 2 kg object moving at 3 m/s will increase its velocity to 5 m/s after 2 m under the action of a constant force parallel to a frictionless surface. the constant force acting on the object is:\n2 n\n4 n\n6 n\n8 n\n10 n\nquestion 3\n1 pts\nif the total work done on an object is positive,\nthe objects velocity will increase\nthe objects velocity will decrease.\nthe kinetic energy of the object will decrease.\nthe objects velocity will not change.\nthe direction of the objects acceleration will be opposite to its displacement.

Answer

Explanation:

Step1: Find the acceleration

Use the equation $v^{2}=u^{2}+2as$, where $v = 5$ m/s, $u = 3$ m/s, $s=2$ m. $a=\frac{v^{2}-u^{2}}{2s}=\frac{5^{2}-3^{2}}{2\times2}=\frac{25 - 9}{4}=\frac{16}{4}=4$ m/s²

Step2: Calculate the force

Use Newton's second - law $F = ma$, with $m = 2$ kg and $a = 4$ m/s². $F=2\times4 = 8$ N

Answer:

Question 2: D. 8 N Question 3: A. The object's velocity will increase