question 5\nnot yet answered\nmarked out of 1.00\nflag question\nwhat is the average kinetic energy (in kj…

question 5\nnot yet answered\nmarked out of 1.00\nflag question\nwhat is the average kinetic energy (in kj mol⁻¹) of a hypothetical gas with molecular weight 46.5 g mol⁻¹ at a temperature of 43.6 °c? do not try to identify the gas.\nanswer:

question 5\nnot yet answered\nmarked out of 1.00\nflag question\nwhat is the average kinetic energy (in kj mol⁻¹) of a hypothetical gas with molecular weight 46.5 g mol⁻¹ at a temperature of 43.6 °c? do not try to identify the gas.\nanswer:

Answer

Explanation:

Step1: Convert Celsius to Kelvin

The temperature in Celsius $T_C = 43.6^{\circ}C$. The conversion formula from Celsius to Kelvin is $T = T_C+ 273.15$. So $T=(43.6 + 273.15)\text{ K}=316.75\text{ K}$.

Step2: Use the formula for average - kinetic energy

The formula for the average kinetic energy per mole of a gas is $\overline{E}_k=\frac{3}{2}RT$, where $R = 8.314\text{ J mol}^{-1}\text{ K}^{-1}$ is the universal gas constant. Substitute $R = 8.314\text{ J mol}^{-1}\text{ K}^{-1}$ and $T = 316.75\text{ K}$ into the formula: $\overline{E}_k=\frac{3}{2}\times8.314\times316.75\text{ J mol}^{-1}$ $\overline{E}_k = 3.94\times10^{3}\text{ J mol}^{-1}$ Convert to kJ/mol: $\overline{E}_k=\frac{3.94\times 10^{3}}{1000}\text{ kJ mol}^{-1}=3.94\text{ kJ mol}^{-1}$

Answer:

$3.94$