quiz - gas laws\nname: ebtesam\nquestions\n13. a carnival worker uses a 56.0ml pressurized helium gas…

quiz - gas laws\nname: ebtesam\nquestions\n13. a carnival worker uses a 56.0ml pressurized helium gas cylinder to blow up balloons. if the balloons are blown up (at constant temperature) to a volume of 3.42l, the pressure of the helium inside of the balloon will be 111kpa. determine the pressure of the helium, inside the pressurized gas cylinder, expressed in the form a.bc×10^d kpa. the values of a, b, c and d are ____ and ____\nyour answer:

quiz - gas laws\nname: ebtesam\nquestions\n13. a carnival worker uses a 56.0ml pressurized helium gas cylinder to blow up balloons. if the balloons are blown up (at constant temperature) to a volume of 3.42l, the pressure of the helium inside of the balloon will be 111kpa. determine the pressure of the helium, inside the pressurized gas cylinder, expressed in the form a.bc×10^d kpa. the values of a, b, c and d are ____ and ____\nyour answer:

Answer

Explanation:

Step1: Apply Boyle's Law

$P_1V_1 = P_2V_2$

Step2: Convert volumes to SI - units

$V_1=56\ mL = 56\times10^{- 3}\ L$, $V_2 = 3.42\ L$, $P_2 = 111\ kPa$

Step3: Rearrange the formula for $P_1$

$P_1=\frac{P_2V_2}{V_1}$

Step4: Substitute the values

$P_1=\frac{111\ kPa\times3.42\ L}{56\times10^{-3}\ L}$ $P_1=\frac{111\times3.42}{56\times10^{-3}}\ kPa$ $P_1=\frac{379.62}{56\times10^{-3}}\ kPa$ $P_1 = 6.779\times10^{3}\ kPa$

Answer:

6, 779