r1 = 50.0 ohm and r2 = 80.0 ohm. they are connected in series with a third resistor, r3, and the total…
r1 = 50.0 ohm and r2 = 80.0 ohm. they are connected in series with a third resistor, r3, and the total resistance of the combination is 200 ohm. what is the value of r3? (unit = ohm)
Answer
Explanation:
Step1: Recall series - resistance formula
For resistors in series, the total resistance $R_{total}=R1 + R2+R3$.
Step2: Rearrange the formula to solve for R3
$R3=R_{total}-R1 - R2$.
Step3: Substitute the given values
Given $R1 = 50.0\ \Omega$, $R2 = 80.0\ \Omega$ and $R_{total}=200\ \Omega$. Then $R3=200 - 50.0-80.0$. $R3 = 70.0\ \Omega$.
Answer:
$70.0$