a radioactive nuclide has 53 protons and 78 neutrons. which is the symbol of this nuclide?\no…

a radioactive nuclide has 53 protons and 78 neutrons. which is the symbol of this nuclide?\no $\frac{53}{78}$i\no $\frac{78}{53}$pt\no $\frac{131}{78}$pt\no $\frac{131}{53}$i

a radioactive nuclide has 53 protons and 78 neutrons. which is the symbol of this nuclide?\no $\frac{53}{78}$i\no $\frac{78}{53}$pt\no $\frac{131}{78}$pt\no $\frac{131}{53}$i

Answer

Explanation:

Step1: Identify the element

The number of protons determines the atomic number and the element. With 53 protons, the element is iodine (I).

Step2: Calculate the mass - number

The mass - number (A) is the sum of protons (Z) and neutrons (N). So, $A=Z + N=53 + 78=131$.

Step3: Write the nuclide symbol

The nuclide symbol is written as $^{A}{Z}X$, where X is the chemical symbol of the element, A is the mass - number, and Z is the atomic number. For iodine with atomic number 53 and mass - number 131, the symbol is $^{131}{53}I$.

Answer:

$^{131}_{53}I$ (the last option)