read the scenario, then answer the questions. a 2 kg ball is thrown upward with a velocity of 15 m/s. what…

Explanation:

Step1: Calculate initial kinetic energy

The formula for kinetic energy is $K = \frac{1}{2}mv^{2}$, where $m = 2\ kg$ and $v=15\ m/s$. $K=\frac{1}{2}\times2\times15^{2}$ $K = 225\ J$

Step2: Use conservation of mechanical - energy

At the maximum - height, the velocity of the ball is $v = 0\ m/s$, so the kinetic energy $K = 0\ J$. According to the conservation of mechanical energy ($E = K+U$, where $E$ is the total mechanical energy, $K$ is the kinetic energy, and $U$ is the potential energy), the total mechanical energy of the ball is conserved. Initially, the total mechanical energy is equal to the initial kinetic energy since the initial potential energy (taking the ground - level as the zero - potential level) is $U = 0\ J$. So at the maximum height, the potential energy $U$ is equal to the initial kinetic energy. $U = 225\ J$

Answer:

225 225