refer to the figure below to answer questions 1-3.\n1. what is the correct description of any change of…
refer to the figure below to answer questions 1-3.\n1. what is the correct description of any change of position farther to the right of zero?\na. positive displacement\nb. positive distance\nc. positive position\nd. positive change of displacement\n2. a dog walks from +4 m to +2 m. which of the following statements is true about the dog’s motion?\na. $x_i = +2$ m\nc. $delta x = +2$ m\nb. $x_f = +2$ m\nd. $v_{avg}=2$ m/s\n3. what is the maximum negative displacement a dog could have if it started its motion at +3 m?\na. +7 m\nc. -3 m\nb. +3 m\nd. -7 m\nuse the number line below to answer the following questions. show all work and yes there is some!
Answer
Explanation:
Step1: Define displacement concept
Displacement is change in position. Positive displacement is when final position is to right of initial position. For a position - based number - line with zero as reference, any change of position farther to the right of zero is positive displacement.
Step2: Analyze dog's motion variables
The initial position of the dog is (x_i = + 4m) and the final position is (x_f=+2m). The displacement (\Delta x=x_f - x_i=2 - 4=-2m). We are not given time information to calculate average velocity (v_{avg}). So the correct variable for final position is (x_f = + 2m).
Step3: Determine maximum negative displacement
If the dog starts at (x_i = + 3m), the maximum negative displacement occurs when it moves to the left - most possible position on the number - line. Assuming the number - line has a minimum value of 0 (not given otherwise), the maximum negative displacement (\Delta x=0 - 3=-3m).
Answer:
- a. positive displacement
- b. (x_f = + 2m)
- c. (-3m)