remarks\nalthough modeling the long - jumpers motion as that of a projectile is an oversimplification, the…

remarks\nalthough modeling the long - jumpers motion as that of a projectile is an oversimplification, the values obtained are reasonable.\nquestion\nhow would the time of the jump and the horizontal distance traveled change if g were changed, for example if the jump could be repeated with the same initial velocity on a different planet? (select all that apply.)\nthe time of the jump increases when g is smaller.\nincreasing the time of the jump has no effect on the displacement.\nthe time of the jump decreases when g is smaller.\nthe displacement increases with increased time of the jump.\nthe displacement decreases with increased time of the jump.\npractice it\nuse the worked example above to help you solve this problem. a long - jumper (as shown in the figure) leaves the ground at an angle of 17.0° to the horizontal and at a speed of 10.8 m/s.\n(a) how long does it take for her to reach maximum height?\n0.320 s\n(b) what is the maximum height?

remarks\nalthough modeling the long - jumpers motion as that of a projectile is an oversimplification, the values obtained are reasonable.\nquestion\nhow would the time of the jump and the horizontal distance traveled change if g were changed, for example if the jump could be repeated with the same initial velocity on a different planet? (select all that apply.)\nthe time of the jump increases when g is smaller.\nincreasing the time of the jump has no effect on the displacement.\nthe time of the jump decreases when g is smaller.\nthe displacement increases with increased time of the jump.\nthe displacement decreases with increased time of the jump.\npractice it\nuse the worked example above to help you solve this problem. a long - jumper (as shown in the figure) leaves the ground at an angle of 17.0° to the horizontal and at a speed of 10.8 m/s.\n(a) how long does it take for her to reach maximum height?\n0.320 s\n(b) what is the maximum height?

Answer

Explanation:

Step1: Analyze vertical - motion formula for time

The time (t) to reach maximum height in vertical - motion under gravity is given by (t=\frac{v_{0y}}{g}), where (v_{0y} = v_0\sin\theta) (initial vertical velocity) and (g) is the acceleration due to gravity. When (g) is smaller, with (v_{0y}) constant, the value of (t) (time of jump to reach maximum height) increases. So, the time of the jump increases when (g) is smaller.

Step2: Analyze horizontal - displacement formula

The horizontal displacement (x = v_{0x}t), where (v_{0x}=v_0\cos\theta) (initial horizontal velocity) and (t) is the time of flight. Since (x) is directly proportional to (t) (with (v_{0x}) constant), the displacement increases with increased time of the jump.

Answer:

The time of the jump increases when (g) is smaller. The displacement increases with increased time of the jump.