which represents the balanced equation for the beta minus emission of phosphorus - 32?\n$_{15}^{32}p\\longrig…

which represents the balanced equation for the beta minus emission of phosphorus - 32?\n$_{15}^{32}p\\longrightarrow_{13}^{28}al + _{2}^{4}he$\n$_{15}^{32}p\\longrightarrow_{14}^{32}si+_{ - 1}^{0}e$\n$_{15}^{32}p\\longrightarrow_{16}^{32}s + _{ - 1}^{0}e$\n$_{15}^{32}p\\longrightarrow_{14}^{32}si+_{ + 1}^{0}e$

which represents the balanced equation for the beta minus emission of phosphorus - 32?\n$_{15}^{32}p\\longrightarrow_{13}^{28}al + _{2}^{4}he$\n$_{15}^{32}p\\longrightarrow_{14}^{32}si+_{ - 1}^{0}e$\n$_{15}^{32}p\\longrightarrow_{16}^{32}s + _{ - 1}^{0}e$\n$_{15}^{32}p\\longrightarrow_{14}^{32}si+_{ + 1}^{0}e$

Answer

Explanation:

Step1: Recall beta - minus decay concept

In beta - minus decay, a neutron in the nucleus changes into a proton, an electron (beta - particle), and an antineutrino. The atomic number (number of protons) increases by 1, and the mass number (sum of protons and neutrons) remains the same. The general form of beta - minus decay is $^{A}{Z}X\rightarrow^{A}{Z + 1}Y+^{0}{- 1}e+\bar{\nu}$. For phosphorus - 32 ($^{32}{15}P$), the mass number $A = 32$ and atomic number $Z=15$. After beta - minus decay, the atomic number will be $Z + 1=16$ and the mass number will remain 32.

Step2: Identify the correct product

The element with atomic number 16 is sulfur (S). So the balanced equation for the beta - minus decay of phosphorus - 32 is $^{32}{15}P\rightarrow^{32}{16}S+^{0}_{- 1}e$.

Answer:

$^{32}{15}P\rightarrow^{32}{16}S+^{0}_{- 1}e$ (the third option in the multiple - choice list)