which represents the balanced nuclear equation for the beta minus decay of co - 60?\n$_{27}^{60}co\\longright…

which represents the balanced nuclear equation for the beta minus decay of co - 60?\n$_{27}^{60}co\\longrightarrow_{26}^{60}fe + _{+1}^{0}e$\n$_{27}^{60}co\\longrightarrow_{28}^{60}ni + _{-1}^{0}e$\n$_{27}^{60}co+_{+1}^{0}e\\longrightarrow_{28}^{60}ni$\n$_{27}^{60}co+_{-1}^{0}e\\longrightarrow_{26}^{60}fe$

which represents the balanced nuclear equation for the beta minus decay of co - 60?\n$_{27}^{60}co\\longrightarrow_{26}^{60}fe + _{+1}^{0}e$\n$_{27}^{60}co\\longrightarrow_{28}^{60}ni + _{-1}^{0}e$\n$_{27}^{60}co+_{+1}^{0}e\\longrightarrow_{28}^{60}ni$\n$_{27}^{60}co+_{-1}^{0}e\\longrightarrow_{26}^{60}fe$

Answer

Answer:

B. ${27}^{60}\text{Co}\longrightarrow{28}^{60}\text{Ni}+_{ - 1}^{0}\text{e}$

Explanation:

Step1: Recall beta - minus decay concept

In beta - minus decay, a neutron in the nucleus changes into a proton, an electron (beta - particle), and an antineutrino. The atomic number (number of protons) increases by 1, while the mass number (sum of protons and neutrons) remains the same.

Step2: Analyze Co - 60 decay

Cobalt - 60 (${27}^{60}\text{Co}$) has an atomic number of 27 and a mass number of 60. After beta - minus decay, the new element should have an atomic number of 27 + 1=28 (which is nickel, Ni) and a mass number of 60. The emitted particle is a beta - particle with symbol ${ - 1}^{0}\text{e}$. So the balanced nuclear equation is ${27}^{60}\text{Co}\longrightarrow{28}^{60}\text{Ni}+_{ - 1}^{0}\text{e}$.