which represents the balanced nuclear equation for the beta plus decay of c - 11?\n$_{6}^{11}c\\longrightarro…

which represents the balanced nuclear equation for the beta plus decay of c - 11?\n$_{6}^{11}c\\longrightarrow_{5}^{11}b + _{+1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{7}^{11}n + _{+1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{7}^{11}n + _{-1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{5}^{11}b + _{-1}^{0}e$

which represents the balanced nuclear equation for the beta plus decay of c - 11?\n$_{6}^{11}c\\longrightarrow_{5}^{11}b + _{+1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{7}^{11}n + _{+1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{7}^{11}n + _{-1}^{0}e$\n$_{6}^{11}c\\longrightarrow_{5}^{11}b + _{-1}^{0}e$

Answer

Explanation:

Step1: Recall beta - plus decay concept

In beta - plus decay, a proton in the nucleus is converted into a neutron, a positron (${+1}^{0}e$), and a neutrino. The atomic number ($Z$) decreases by 1 and the mass number ($A$) remains the same. For carbon - 11 (${6}^{11}C$), the mass number $A = 11$ and atomic number $Z=6$. After beta - plus decay, the new element will have atomic number $Z = 6 - 1=5$ and mass number $A = 11$. The element with atomic number 5 is boron ($B$). The balanced nuclear equation is ${6}^{11}C\rightarrow{5}^{11}B + _{+1}^{0}e$.

Answer:

${6}^{11}C\rightarrow{5}^{11}B + _{+1}^{0}e$ (the first option)